$arr = array ( 0 => array ( 0 => 'su14031300617', 'po_num' => 'su14031300617', ), 1 => array ( 0 => 'su14031300623', 'po_num' => 'su14031300623', ), 2 => array ( 0 => 'su14031300626', 'po_num' => 'su14031300626', ), 3 => array ( 0 => 'su14031300627', 'po_num' => 'su14031300627', ), 4 => array ( 0 => 'su14031300616', 'po_num' => 'su14031300616', ), 5 => array ( 0 => 'su14031300618', 'po_num' => 'su14031300618', ), 6 => array ( 0 => 'su14031300622', 'po_num' => 'su14031300622', ), 7 => array ( 0 => 'su14031300624', 'po_num' => 'su14031300624', ), 8 => array ( 0 => 'su14031300625', 'po_num' => 'su14031300625', ),)
假设su14031300617这项，所在数组的位置是8项中的第1项，表示为 1/8，通过序号可求得。请问怎么求解？
回复讨论(解决方案) foreach($arr as $k=>$tmp) { if('su14031300617' == $tmp[0]) { return ($k+1) . '/' . count($arr); }}return false;