public string[] split(string regex, int limit)
当limit>0时,则应用n-1次
public static void main(string[] args) { string s = "boo:and:foo"; string[] str = s.split(":",2); system.out.print(str[0] + "," + str[1]); }
结果:
boo,and:foo
当limit<0时,则应用无限次
public static void main(string[] args) { string s = "boo:and:foo"; string[] str = s.split(":",-2); for(int i = 0 ; i < str.length ; i++){ system.out.print(str[i] + " "); } }
结果:
boo and foo
当limit=0时,应用无限次并省略末尾的空字符串
public static void main(string[] args) { string s = "boo:and:foo"; string[] str = s.split("o",-2); for(int i = 0 ; i < str.length ; i++){ if( i < str.length - 1) system.out.print("(" + str[i] + "),"); else system.out.print("(" + str[i] + ")"); } }
结果:
(b),(),(:and:f),(),()
public static void main(string[] args) { string s = "boo:and:foo"; string[] str = s.split("o",0); for(int i = 0 ; i < str.length ; i++){ if( i < str.length - 1) system.out.print("(" + str[i] + "),"); else system.out.print("(" + str[i] + ")"); } }
结果:
(b),(),(:and:f)
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