#打印斐波拉契数列#!/usr/bin/pythondef feibolaqi(n): if n == 0 or n == 1: return n else: return feibolaqi(n-1) + feibolaqi(n-2)num = int(raw_input('please input a int:'))if num >= 0: print 'feibolaqi(%d) is %d' % (num,feibolaqi(num))else: print 'input is wrong'
希望本文所述对大家的python程序设计有所帮助。