public function pai3(&$actionno, &$actiontime, $time=null){
$this->settimeno($actiontime, $time);
//echo $actiontime,' ',date('y-m-d h:i:s', $time);
if($actiontime >= date('y-m-d h:i:s', $time)){
$actionno = date('yz', $time)-6;
}else{
$actionno = date('yz', $time)-6;
$actiontime=date('y-m-d 18:30', $time);
}
}
上面代码读取的年和号,如201456我想改成2014056增加一位,请问怎么改?
------解决方案--------------------
public function pai3(&$actionno, &$actiontime, $time=null){
$this->settimeno($actiontime, $time);
//echo $actiontime,' ',date('y-m-d h:i:s', $time);
$year = date('y', $time);
$day = str_pad(date('z',$time),3,'0',str_pad_left);
$times = $year.$day;
if($actiontime >= date('y-m-d h:i:s', $time)){
$actionno = $times-6;
}else{
$actionno = $times-6;
$actiontime=date('y-m-d 18:30', $time);
}
}
