想要合并这个两个数组，判断条件，id,b两个元素都相同的情况的num值相加。新数组键值重新排列0 1 2 3
求高手指点。谢谢。
回复讨论(解决方案) array_merge($fruits, $numbered); 合并数组就行了啊
array_merge($fruits, $numbered); 合并数组就行了啊
大哥注意看条件
判断条件，id,b两个元素都相同的情况的num值相加。
有人在吗？
$arr1=array( 0=>array( 'id' => '2', 'b' => 0, 'num' => 4 ), 1=>array( 'id' => '1', 'b' => 0, 'num' => 4 ) ); $arr2=array( 1=>array( 'id' => '3', 'b' => 0, 'num' => 4 ), 2=>array( 'id' => '2', 'b' => 0, 'num' => 4 ) );foreach($arr1 as $v) $res[$v[id]_$v[b]] = $v;foreach($arr2 as $v) if(isset($res[$v[id]_$v[b]])) $res[$v[id]_$v[b]]['num'] += $v['num']; else $res[$v[id]_$v[b]] = $v;print_r(array_values($res));
array( [0] => array ( [id] => 2 [b] => 0 [num] => 8 ) [1] => array ( [id] => 1 [b] => 0 [num] => 4 ) [2] => array ( [id] => 3 [b] => 0 [num] => 4 ))
$arr1=array( 0=>array( 'id' => '2', 'b' => 0, 'num' => 4 ), 1=>array( 'id' => '1', 'b' => 0, 'num' => 4 ) ); $arr2=array( 1=>array( 'id' => '3', 'b' => 0, 'num' => 4 ), 2=>array( 'id' => '2', 'b' => 0, 'num' => 4 ) );foreach($arr1 as $v) $res[$v[id]_$v[b]] = $v;foreach($arr2 as $v) if(isset($res[$v[id]_$v[b]])) $res[$v[id]_$v[b]]['num'] += $v['num']; else $res[$v[id]_$v[b]] = $v;print_r(array_values($res));
array( [0] => array ( [id] => 2 [b] => 0 [num] => 8 ) [1] => array ( [id] => 1 [b] => 0 [num] => 4 ) [2] => array ( [id] => 3 [b] => 0 [num] => 4 ))
非常感谢，看了以后思路又开阔了不少，收获良多，再次谢谢大神解答。