解决方案示例 1input: a string expression with bracket is as follows:(x+y)+(z+q)the output is as follows:x+y+z+q
示例 2the input is as follows:(x-y+z)-p+qthe output is as follows:x-y+z-p+q
algorithmrefer an algorithm to remove the brackets from a given input.
step 1: declare and read the input at runtime.
step 2: traverse the string.
step 3: copy each element of the input string into new string.
step 4: if anyone parenthesis is encountered as an element, replace it with empty space.
examplefollowing is the c program to remove the brackets from a given input −
#include<stdio.h>int main(){ int i=0,c=0,j=0; char a[100],b[100]; printf("
enter the string :"); scanf("%s",a); while(a[i]!='\0'){ if((a[i]=='(') && (a[i-1]=='-')){ (c=0)?j=i:j=c; while(a[i]!=')'){ if(a[i+1]=='+') b[j++]='-'; else if(a[i+1]=='-') b[j++]='+'; else if(a[i+1]!=')') b[j++]=a[i+1]; i++; } c=j+1; } else if(a[i]=='(' && a[i-1]=='+'){ (c==0)?j=i:j=c; while(a[i]!=')'){ b[j++]=a[i+1]; i++; } j–; c=j+1; } else if(a[i]==')'){ i++; continue; } else { b[j++]=a[i]; } i++; } b[j]='\0'; printf("%s",b); return 0;}
输出执行上述程序时，会产生以下输出 -
enter the string:(x+y)-zx+y-z
以上就是给定输入的c程序，移除括号的详细内容。