a(ax,ay),b(px,py)为两个点 （x1,y1）,(x2,y2)为矩形的左上角和右下角坐标 ,判断a，b两点是否和矩形相交 def judge(ax, ay, px, py, x1, y1, x2, y2): #转换为真除法 ax, ay, px, py = float(ax), float(ay), float(px), float(py) x1, y1, x2, y2 = float(x1), float(y1), float(x2), float(y2) #判断矩形上边线和两点直线相交的点 sx = (y1 - ay) * (px - ax) / (py - ay) + ax if sx >= x1 and sx = x1 and sx = y1 and zy <= y2: return true #判断矩形右边线和两点直线相交的点 yy = (y2 - ay) * (x2 - ax) / (px - ax) + ay if yy = y2: return true return falseax = raw_input()ay = input()px = input()py = input()x1 = input()y1 = input()x2 = input()y2 = input()print judge(ax, ay, px, py, x1, y1, x2, y2)
希望本文所述对大家的python程序设计有所帮助。