php code@$judge=$_get[speed];if(@$keyboard=$_get[keyboard]){$keyboardfinal=100;}if(@$judge==1){if($keyboard0){@$keyboardfinal=50; }}if(@$judge==2){if(@$keyboard0){$keyboardfinal=50; }}if(@$judge==3 && (@$keyboard0)){$keyboardfinal=50; }
如上代码~为什么在第二，三，四个if语句中，即使条件成立任然无法使$keyboardfinal=50;成立为什么呢？
------解决方案--------------------
@$judge=$_get[speed];
为什么变量前面加@有什么特别效果吗？
------解决方案--------------------
不明白楼主为什么要加那么多错误控制符，如果不报出错误，你怎么修改代码呢？
将楼主的代码修改了下：
php code$judge = 1;$keyboard = 35;$keyboardfinal = null;switch($judge){ case 1: if($keyboard0) $keyboardfinal=50; break; case 2: if($keyboard0) $keyboardfinal=50; break; case 3 && ($keyboard0): $keyboardfinal=50; break;}echo keyboardfinal-->>.$keyboardfinal;#50
------解决方案--------------------
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php code
@$judge=$_get[speed];
if(@$keyboard=$_get[keyboard]){
$keyboardfinal=100;
}
if(@$judge==1){
if($keyboard0){
@$keyboardfinal=50;
}
}
if(@$judge==2){
if(@$keyb……