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SQL存储过程实现SPSS交叉表

2024/5/11 1:06:33发布21次查看
@str4=stuff((select ', '+colname1 from (select distinct 1 as id , 't1.['+colname1+'], t1.['+colname1+']/convert(float,t2.['+colname1+']) as [n%]' as colname1 from temp_crosstable_001) t where id=t.id for xml path('')),1,1,'')
        @str4=stuff((select ', '+colname1 from (select distinct 1 as id , 't1.['+colname1+'], t1.['+colname1+']/convert(float,t2.['+colname1+']) as [n%]' as colname1 from temp_crosstable_001) t where id=t.id for xml path('')),1,1,'') 

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