情况是这样的
a表字段user dt dg
a 15 10
b 17 15
b表字段user title jh
a xxx 1
b xxx 0
b xxxxx 0
a xxxxx 0
b xxxxx 1
想要实现的是，根据a表中的user与b表中的user值得出 b表中的有多少与该user相关的数据，按数据条数从多到少排序，然后输出结果为
user dt jh b表中的条数
b 17 1 3
a 15 1 2
------解决方案--------------------
select a.*, t.jh from a, (select user,count(*) as jh from b) t where a.user=t.user order by t.jh desc
------解决方案--------------------
select a.user,a.dt,sum(b.jh) as jh,count(b.user) as counter from a inner join b on a.user=b.user group by b.user order by counter desc;