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未定义的变量!该怎么解决

2024/3/31 21:42:13发布12次查看
未定义的变量!
源代码!
function opendb($sql){
$link = mysql_connect($server_db, $user_db, $password_db)or die(could not connect:.mysql_error());
mysql_select_db($database_db, $link);
$result = mysql_query($sql);
return $result;
}
opendb(select * from config where id = 1);
$row = mysql_fetch_array($result);
echo $row[classname];
错误提示!
notice: undefined variable: result in e:\wwwroot\include\config.int.php on line 36
warning: mysql_fetch_array(): supplied argument is not a valid mysql result resource in e:\wwwroot\include\config.int.php on line 36
------解决方案--------------------
$result=opendb(select * from config where id = 1);
$row = mysql_fetch_array($result);
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