本帖最后由 lazygc520 于 2013-06-07 09:37:32 编辑
$row2[0],'count'=>$row2[1]); } print_r($var); }// echo $a[$k]['5'].'
';?>
得到的结果：
array( [0] => array ( [lotno] => 3207 [count] => 15 ))array( [0] => array ( [lotno] => 3207 [count] => 15 ))array( [0] => array ( [lotno] => 3206 [count] => 12 ) [1] => array ( [lotno] => 3207 [count] => 3 ))array( [0] => array ( [lotno] => 3207 [count] => 15 ))array( [0] => array ( [lotno] => 3207 [count] => 15 ))array( [0] => array ( [lotno] => 3218 [count] => 15 ))array( [0] => array ( [lotno] => 3218 [count] => 15 ))array( [0] => array ( [lotno] => 3218 [count] => 15 ))array( [0] => array ( [lotno] => 3218 [count] => 15 ))array( [0] => array ( [lotno] => 3218 [count] => 15 ))array( [0] => array ( [lotno] => 3218 [count] => 15 ))array( [0] => array ( [lotno] => 3218 [count] => 15 ))array( [0] => array ( [lotno] => 3218 [count] => 15 ))array( [0] => array ( [lotno] => 3218 [count] => 15 ))array( [0] => array ( [lotno] => 3218 [count] => 15 ))array( [0] => array ( [lotno] => 3218 [count] => 15 ))array( [0] => array ( [lotno] => 3218 [count] => 15 ))
如何将这些二维数组合并到一个数组中并按lotno排序？
若lotno相同时，将对应count的值相加。请问下如何处理？
回复讨论(解决方案) $sql = select distinct b.packageno,a.stock_no from `stock_detail` as a,`kw_manage` as b where a.stock_no = '.$stockno.' and a.cust_no = replace( b.cust_no, ' ', '' );$result = mysql_query($sql);$res = array(); //设置一个用于存放结果的数组while($row = mysql_fetch_array($result,mysql_assoc)){ $sql2 = select lotno,count(lotno) from `vp_barcode_2d_y` where packageno = '.$row['packageno'].' group by lotno order by lotno asc; $result2 = mysql_query($sql2); $var = array(); while($row2 = mysql_fetch_array($result2,mysql_num)) { if(isset($res[$row2[0]])) $res[$row2[0]]['count'] += $row2[1]; else $res[$row2[0]] = array('lotno'=>$row2[0],'count'=>$row2[1]); }}ksort($res); //因键名已处理成 lotno 的值，所以按键名排序就是按 lotno 排序