sql 计算给定日期是当年的第几天语句
declare @date datetime;
set @date = getdate()
select datepart(dayofyear,@date) [dayofyear];
select datename(dayofyear,@date) [dayofyear];
--另一种思路：当前日期与上年最后一天差的天数
select datediff(day,dateadd(year,datediff(year,0,@date),-1),@date)[dayofyear]
go