您好,欢迎来到三六零分类信息网!老站,搜索引擎当天收录,欢迎发信息

在sql Server自定义一个用户定义星期函数

2024/3/6 21:32:01发布15次查看
程序开发过程中需要做周别统计与显示报表。在做之前,得先找出所在年份周别的开始日期与结束日期。每年每周的开始与结束日期都不尽相同。为了该功能,在sql server自定义一个用户定义星期函数
文件:.wmv;大小:19,535kb;长度:00:26:39。
下载地址:
以下内容于20120105更新:
2012年刚到,开发的软件使用这个函数发现bug。2012年第一周应该是2012-01-01至2012-01-07,但此函数却把2012-01-08至2012-01-14当作第一周。
就此bug对此函数修改如下:
代码如下:
set ansi_nulls on
go
set quoted_identifier on
go
alter function [dbo].[udf_week]
(
@startyear int,
@endyear int
)
returns @week table([weekid] int identity(1,1) primary key,[year] [int] null,[week] [int] null,[startdate] [datetime] null,[enddate] [datetime] null)
as
begin
declare @yearstartdate datetime
declare @yearenddate datetime
declare @weekstartdate datetime
declare @weekenddate datetime
declare @weeks int
while @startyear begin
set @yearstartdate = cast((cast(@startyear as varchar(4)) + '-01-01') as datetime)
set @yearenddate= cast((cast(@startyear as varchar(4))+ '-12-31') as datetime)
set @weeks = 1
if datepart(dw,@yearstartdate) > 4
set @yearstartdate = dateadd(day,(8 - datepart(dw,@yearstartdate)) ,@yearstartdate)
else
set @yearstartdate = dateadd(day,(-(datepart(dw,@yearstartdate)-1)),@yearstartdate)
set @weekstartdate = @yearstartdate
set @weekenddate = dateadd(day,6,@weekstartdate)
while datediff(day,@weekstartdate,@yearenddate) >= 4
begin
insert into @week([year],[week],[startdate],[enddate]) values (@startyear,@weeks,@weekstartdate,@weekenddate)
set @weeks = @weeks + 1
set @weekstartdate = @weekstartdate + 7
set @weekenddate = @weekenddate + 7
end
set @startyear = @startyear + 1
end
return
end
该用户其它信息

VIP推荐

免费发布信息,免费发布B2B信息网站平台 - 三六零分类信息网 沪ICP备09012988号-2
企业名录 Product